[tex]\frac{6c - 3}{3c^{2} - 12} = \frac{3(2c) - 3(1)}{3(c^{2}) - 3(4)} = \frac{3(2c - 1)}{3(c^{2} - 4)} = \frac{2c - 1}{c^{2} - 4} = \frac{2c - 1}{c^{2} + 2c - 2c - 4} = \frac{2c - 1}{c(c) + c(2) - 2(c) - 2(2)} = \frac{2c - 1}{c(c + 2) - 2(c + 2)} = \frac{2c - 1}{(c - 2)(c + 2)}[/tex]
Domain: ±2
