Respuesta :

Willchemistry
Molar mass FeSO₄ =151.908 g/mol

Volume = 450 mL / 1000 = 0.45 L

1 mol ----------- 151.908 g
n mol ----------- 0.8 g

n = 0.8 * 1 / 151.908

n = 0.00526 moles 

M = n / V

M = 0.00526 / 0.45

M = 0.01168 mol/L⁻¹

hope this helps!

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