HCl(aq) ------> H⁺(aq) + Cl(aq)
↓ ↓ ↓
i : 0.111 M 0 0
v: - 0.111 M +0.111 M +0.111 M
_______________________________
eq: 0 +0.111 M +0.111 M
HCl is a strong acid, so it ionizes 100% in solution :
PH = - log [ H+]
PH = - log [ 0.111]
PH = 0.9546
hope this helps!
