Answer:
We have to evaluate:
[tex]\frac{3x^2+4 x +5}{x+5}\\\\=\frac{3x^2+15 x-11 x-55+55+5}{x+5}\\\\=\frac{3x^2+15 x-11 x-55+60}{x+5}\\\\= \frac{3 x \times (x+5)-11 \times (x+5)+60}{x+5}\\\\= \frac{3 x \times (x+5)}{x+5} -\frac{11 \times (x+5)}{x+5}+\frac{60}{x+5}\\\\= 3 x -11 +\frac{60}{x+5}[/tex]
Now the degree of numerator is less than degree of the denominator, so, further evaluation is not possible.
Remainder = 60
Quotient = 3 x -11
