Answer:
[tex]\frac{9(x+4)}{x+2}[/tex]
Step-by-step explanation:
factorise the quadratics on the numerator/ denominator
x² + 8x + 16 = (x + 4)(x + 4)
x² + 6x + 8 = (x + 2)(x + 4)
[tex]\frac{27(x^2+8x+16)}{3(x^2+6x+8)}[/tex]
= [tex]\frac{27(x+4)(x+4)}{3(x+2)(x+4)}[/tex]
cancel the 27 and 3 (27 ÷ 3) = 9 and (x + 4) on numerator/denominator
= [tex]\frac{9(x+4)}{x+2}[/tex]
