Answer:
23.8 m
Explanation:
The distance travelled by the zebra can be calculated by using the equation:
[tex]d=ut+\frac{1}{2}at^2[/tex]
where
u is the initial velocity
t is the time
a is the acceleration
For this zebra,
u = 0 since it starts from rest
[tex]a=1.9 m/s^2[/tex] is the acceleration
Substituting t = 5 s, we find the distance travelled by the zebra:
[tex]d=0+\frac{1}{2}(1.9)(5)^2=23.8 m[/tex]
