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  • 13-11-2018
  • Mathematics
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(-7b^5+42b^4) divided by 7b

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apologiabiology
apologiabiology apologiabiology
  • 13-11-2018

remember that [tex]\frac{a+b}{c}=\frac{a}{c}+\frac{b}{c}[/tex]

also remmber that [tex]\frac{x^a}{x^b}=x^{a-b}[/tex]

also remember [tex]\frac{ab}{cd}=(\frac{a}{c})(\frac{b}{d})[/tex]


therefore

[tex]\frac{-7b^5+42b^4}{7b}=[/tex]

[tex]\frac{-7b^5}{7b}+\frac{42b^4}{7b}=[/tex]

[tex](\frac{-7}{7})(\frac{b^5}{b^1})+(\frac{42}{7})(\frac{b^4}{b^1})=[/tex]

[tex](-1)(b^{5-1})+(6)(b^{4-1})=[/tex]

[tex]-b^4+6b^3[/tex]

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