Kim rolls a dice and flips a coin.
For coin: we have either H or T
For dice: we have 1, 2, 3, 4, 5 or 6
On a coin, the probability of heads: [tex]\frac{1}{2}[/tex]
On a dice, the probability of getting 2 : [tex]\frac{1}{6}[/tex]
Hence, the probability of getting a 2 and a head is
[tex]\frac{1}{2}\times\frac{1}{6}[/tex] = [tex]\frac{1}{12}[/tex]
So, the probability that Kim gets a 2 and a head is [tex]\frac{1}{12}[/tex]
