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  • 12-11-2018
  • Mathematics
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Find three consecutive odd integers such that twice the sum of the first and third exceeds the second by fifteen

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Аноним Аноним
  • 12-11-2018

Let the first integer be x , then second = x+2 and third = x + 4 and

2(x + x+4) = x + 2 + 15

4x + 8 = x + 17

3x = 17 - 8 = 9

x = 3

So the required numbers are 3, 5. and 7   (answer)

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