Given data:
Density of iron (Fe) = 7.9 g/cm3
Length of one side of the iron cube = 1.64 * 10^2 cm
Now, the volume (V) of a cube in which the length of the side is 'a' cm is given as:
V = a^3
Volume of iron cube = (1.64 *10^2 cm)^3 = 4.41 * 10^6 cm3
The density (D) of an object of mass (m) and volume (V) is given as:
D = m/V
or, m = D*V
Therefore, mass of iron cube = 7.9 g/cm3 * 4.41 * 10^6 cm3
= 34.84 *10^6 g
