[tex]a(c+b)=d\ \ \ \ |\text{use distributive property}\\\\ac+ab=d\ \ \ \ |-ab\\\\ac=d-ab\ \ \ \ \ |:a\neq0\\\\\boxed{c=\dfrac{d-ab}{a}}[/tex]
I think its this C=\frac{d-ab}{a}[/tex]
