Given equation of hyperbola is
[tex]\frac{(x-1)^{2}}{25}-\frac{(y+3)^{2}}{9}=1[/tex]
Given hyperbola is the horizontal hyperbola
The standard form of the horizontal hyperbola is
[tex]\frac{(x-h)^{2}}{a^{2}}-\frac{(y-k)^{2}}{b^{2}}=1[/tex]
When we compare these two equations, we get
h = 1, a = 5 , k = -3 and b = 3
Length of the transverse axis = 2a
Plug in the value of 'a' as 5
So,Length of the transverse axis = 2(5) = 10
