DisneyLover121502
DisneyLover121502 DisneyLover121502
  • 14-08-2018
  • Mathematics
contestada

Sin^2x/cos^2 + sinxcscx = sec^2x Identify it, please explain so I know how you did it, thanks

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Bladerunner1976
Bladerunner1976 Bladerunner1976
  • 14-08-2018

[tex] \frac{sin^2x}{cos^2x} + sin x *cscx\\ tan^2x + \frac{sin x}{sin x} \\ tan^2x + 1\\ sec^2x [/tex]

[tex] \frac{sin^2x}{cos^2x} = tan^2x [/tex]

[tex] csc x = \frac{1}{sinx} [/tex]

[tex] tan^2x + 1 = sec^2x [/tex]

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