we are given
[tex] f(x)=x^3-64 [/tex]
Since, we have to find zeros
so, we can set f(x)=0
and then we can solve for x
[tex] f(x)=x^3-64=0 [/tex]
[tex] x^3-64=0 [/tex]
We will add both sides 64
[tex] x^3-64+64=0+64 [/tex]
[tex] x^3=64 [/tex]
Take cube root both sides
[tex] \sqrt[3]{x^3} =\sqrt[3]{64} [/tex]
[tex] x=4 [/tex]...........Answer
