f(x)=x^3-7x^2+6x
The zeros of the function
x^3-7x^2+6x = 0
x(x^2 -7x +6) = 0
x(x - 6)(x - 1) = 0
x = 0
x - 6 = 0; x = 6
x - 1 = 0; x = 1
Answer
x = 0, 1 , 6
