Calculate the cell potential, the equilibrium constant, and the free energy change for ba(s) + mn2+

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13-08-2018
Chemistry

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Calculate the cell potential, the equilibrium constant, and the free energy change for ba(s) + mn2+

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RamenNoodle10 RamenNoodle10 · Answer 1 · 2018-08-13T08:27:11+02:00

RamenNoodle10 RamenNoodle10

13-08-2018

Calculate the cell potential, the equilibrium constant, and the free energy change for: Ba(s) + Mn2+(aq)(1M)=bA2+(aq)(1M)+Mn(s) given the following E values:Ba2+ +2e=Ba(s) E=-290V and Mn2+(aq)+2e=Mn(s) E=-1.18V

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