The standard form of a linear equation: Ax + By = C.
The slope-point formula:
[tex]y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have:
[tex]J(-3,\ 11)\to x_1=-3,\ y_1=11\\K(1,\ -3)\to x_2=1,\ y_2=-3[/tex]
Substitute:
[tex]m=\dfrac{-3-11}{1-(-3)}=\dfrac{-14}{4}=-\dfrac{7}{2}\\\\y-11=-\dfrac{7}{2}(x-(-3))\\\\y-11=-\dfrac{7}{2}x-\dfrac{21}{2}\ \ \ \ |\cdot2\\\\2y-22=-7x-21\ \ \ |+22\\\\2y=-7x+1\ \ \ \ |+7x\\\\7x+2y=1[/tex]
Answer: JK: 7x + 2y = 1
