TheWrathfullKing
TheWrathfullKing TheWrathfullKing
  • 14-06-2018
  • Mathematics
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gmany
gmany gmany
  • 14-06-2018
We know:
[tex]a^{-n}=\dfrac{1}{a^n}[/tex]
therefore
[tex]2a^{-4}m^5=2\cdot\dfrac{1}{a^4}\cdot m^5=\dfrac{2m^5}{a^4}[/tex]
Answer: B 2m^5/a^4

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