Respuesta :

sqdancefan
Subtract the right side and the equation becomes

[tex]\dfrac{-3d}{d^2-2d-8}+\dfrac{3}{d+4}+\dfrac{2}{d+2}=0\\\\\dfrac{-3d+3(d+2)+2(d-4)}{(d+2)(d-4)}=0\\\\\dfrac{2d-2}{(d+2)(d-4)}=0\\\\2d=2\\\\d=1[/tex]

The solution is d=1.
bobbiesmith824

Answer: the solution to the answer is d=1


Step-by-step explanation:


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