Bruhhh2k17
Bruhhh2k17 Bruhhh2k17
  • 13-06-2018
  • Mathematics
contestada

Geometry help please. I would like it if you would show work

Geometry help please I would like it if you would show work class=

Respuesta :

Asdfjkadfjkakjf Asdfjkadfjkakjf
  • 16-12-2018

Answer:

AB=sqrt(53)

Step-by-step explanation:

consider the right angle triangle of the top rectangle w sides of 6 n 4

diagonal^2 = 6^2 + 4^2

consider the right angle triangle of the diagonal, AB and 1

AB^2 = diagonal^2 + 1^2

= 6^2 + 4^2 + 1^2

= 36 + 16 + 1

=53

AB=sqrt(53)

ans is a

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