rcmhargoux4554 rcmhargoux4554
  • 13-06-2018
  • Mathematics
contestada

A single cell amoeba doubles every 2.5 days how many days will it take one amoeba to reach a population of 10000

Respuesta :

btobislifeu
btobislifeu btobislifeu
  • 13-06-2018
The answer is 33.25 days

using the general formula for growth:

A = Pe^(rt)

get first the value of r

2 = 1e^(2.5r)
ln 2 = ln e^(2.5r)
r = 0.277

Then use this rate to solve for the main problem:

10000 = 1e^(0.277xt)
solving for t using the same procedure above, we will get:

t = 33.25 days
Answer Link

Otras preguntas

the suffix -iasis means _____.a. the study ofb. repairc. a condition d. incision​
Please help solve! 20 pts up for grabs
please help! 10 points, thank you :)
Find 7.4 times the difference between 87 and 24.
Help and try to explain please, and thank you.
Mr. Green teaches band, choir, and math. This year, he has 57 students that take at least one of his classes. He teaches band to 25 students. There are 9 studen
What are the texture issues in the Trail Mix snacks?
Explain the difference between a Type 1 significance error and a Type 2 significance error
A geologist finds this ridge of sediment while out in the field. The geologist notices a glacier in the distance. What feature is this ridge? kettle loess morai
3y+24 4y-5 find value of y​