Respuesta :

1rstar
Heya !

Given Geometric series -

[tex] - 3 - \dfrac{3}{2} - \dfrac{3}{4} - \dfrac{3}{8} - \dfrac{3}{18} \: \: ... \: \: \infty [/tex]

[tex]
Here \: , \: first \: term \: = \: -3 = a \\
Common \: ratio \: = \: \dfrac{1}{2} = r \\ \\ [/tex]

[tex]Sum \: of \: Infinite \: Geometric \: \\ Progression \: with \: first \: term \: a \: and \: \\ common ratio \: r \: is \: \: \frac{a}{1 - r}
\\ \\
Sum \: = \dfrac{ - 3}{ \dfrac{ 1}{2} } = - 6 \: \: \: \: \: \: \: \: Ans. [/tex]

Hope it helps you :)

Otras preguntas