desmondwinters desmondwinters

11-06-2018
Mathematics

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(a^2 + 3a - 18 / a^2 - 5a +6)(5a - 10 / a^2 -36)

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mkryukova19 mkryukova19

11-06-2018

[tex] \frac{a^{2}+3a-18}{a^2-5a+6} * \frac{5a-10}{a^{2}-36} = \frac{(a+6)(a-3)}{(a-2)(a-3)} * \frac{5(a-2)}{(a+6)(a-6)} = \frac{5}{a-6} , where a \neq 2, a \neq 3, a \neq +6,a \neq -6 [/tex]

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