Respuesta :

PBCHEM
Given: Half life of Rn = 3.8 days
Therefore in 15 days, system crosses 15/3.8 = 3.94 ≈ 4 half-life

Now, Initial amount of Rn = 65 g

∴ Amount of Rn left after 4 half life i.e. 15 days = [tex] \frac{65}{2^4} [/tex] = 4.06 g

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