Respuesta :

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[tex]x+2+\left[4x-\dfrac{x^2+6x+8}{x+4}\right]=x+2+\left[4x-\dfrac{x^2+4x+2x+8}{x+4}\right]\\\\=x+2+4x-\dfrac{x(x+4)+2(x+4)}{x+4}=5x+2-\dfrac{(x+2)(x+4)}{x+4}\\\\=5x+2-(x+2)=5x+2-x-2=4x[/tex]
Answer: 4x

Answer:

4x

Step-by-step explanation:

correct on edge 2021

-RZA

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