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12-04-2024
Chemistry

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Consider the following decay: _(95)^(242)Am → _(93)^(238)Np + alpha. _(95)^(242)Am has a mass of 242.0595492u, _(93)^(238)Np has a mass of 238.0509464u, and alpha has a mass of 4.002603u. Determine the mass of _(93)^(238)Np + alpha.

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