Consider the power series
p(x) = ∑₍ₙ₌₁₎[infinity]((12-x) ⁿ/(2ⁿ√(n) )

Then the radius of absolute convergence of p(x) is R =
If the interval of convergence of p has end points a= b=x=a,p(x) x

A) R = 1; a = -1, b = 11
B) R = 2; a = -10, b = 10
C) R = 3; a = -11, b = 12
D) R = 4; a = -12, b = 12