What is the mass of H3BO3 in grams that is produced from the reaction of 39.2 g of B₂H, in excess water?

Molar masses are given below.

MM H3BO3 = 61.834 g/mol
MM B₂H6 = 27.668 g/mol

B₂H6 (g) + 6H₂O () → 2 H3BO3 (s) + 6 H₂ (9)